CALCULUS
In around 450BC, a Greek Mathematician, Zeno of Elea, said, "If a
body moves from A to B then before it reaches B it passes through the
mid-point, say B1 of AB. Now to move to B1 it must first reach the mid-point
B2 of AB1 . Continue this argument to see that A must move through an
infinite number of distances and so cannot move." This probably is
the first record of a probem involving basics of calculus.
We all know...
Speed = Distance/ Time
Realistically, the above formula gives us the average speed. A car seldom
travels at a constant speed. An apple does not fall at a constant speed.
So if you wanted to find instantaneous speed, using the above formula,
the answer would be zero/ zero. Just like a picture of a moving car. It
seems stopped. The car was actually moving but has no speed at that instant.
How come.
Newton's discovery of modern calculus, may very well have been inspired
by the apple falling from a tree. As an apple falls, it moves faster and
faster; that is, it has not only a velocity but an acceleration. Newton
expressed this mathematically by supposing that at any stage of its motion
the apple drops a small additional distance s (delta s) during a brief
additional time interval t (delta t). Then the velocity is very nearly
equal to the distance "s" divided by the time "t"
i.e., s/t. The exact velocity v would be the limit of s/t as t gets closer
and closer to zero or, as we say, approaches zero. That is,

For example a runner is running and the following table gives the positions
of the runner at different times:
| At Time
"t" seconds |
The distance
"s" meters from 0 point |
| 1.00 |
1.00 |
| 1.01 |
1.02 |
| 1.10 |
1.21 |
| 1.20 |
1.44 |
| 1.50 |
2.25 |
| 2.00 |
4.00 |
| 3.00 |
9.00 |
It is obvious from the above table that the runner covered a distance
of 9 meters in three seconds. The velocity would be as follows:
v = s/t = 9/3=3 meters/ second.
But this is the average quantity calculated for the total 9 meters covered.
Our observations started from t=1, so the average velocity for the observed
part of the run are as follows:
v = Δs/Δt = (9-1)/(3-1) = 4m/s
Lets say if we want to find the instantaneous velocity at t=1.00, we will
have;
vinst = Δs/Δt lim t=1 = (1.02-1.00)/(1.01/1.00)
= 2.00 meters/ second
We see that
the instantaneous velocity gives us more specific information than the
average velocity. At a given point in time or as the runner approaches
t=1, or a graph showing a complex curve/ behaviour, the instantaneous
value can be represented by using the concepts of calculus.
The quantity ds/dt is called the derivative of s with respect to t, or
the rate of change of s with respect to t. It is possible to think of
ds and dt as numbers whose ratio ds/dt is equal to v; ds is called the
differential of s, and dt the differential of t. Just as velocity is the
rate of change, or derivative, of the distance with respect to time, so
the acceleration is the rate of change, or derivative, of the velocity
with respect to time. Therefore a, the acceleration, would be
where v is the increase in velocity that occurs during the interval t.
Since a is the derivative of v and v is the derivative of s, a is called
the second derivative of s:
To find derivatives of s with respect to t, the dependence of s on t must
be known; in other words, s must be expressed as a function of t. Usually
this functional dependence is stated as a formula relating s and t. That
part of calculus dealing with derivatives is called differential calculus.
Given s as
a function of t, the derivative (that is, v) of s can be found. Conversely,
if v is known it is possible to work backward to get s. This process of
finding what is called the anti-derivative of v is begun by rewriting
the equation v = ds/dt as ds = vdt. The quantity s is here regarded as
the anti-differential of ds, denoted by a special symbol called an integral
sign:
The last equation specifies s the integral of v with respect to t. That
part of calculus dealing with integrals is called integral calculus. Applications
of integral calculus involve finding the limit of a sum of many small
quantities, such as the rectangular slices of an irregular plane figure.
As seen above, Calculus is a mathematical study of continuous change.
The primary importance of calculus in the hard sciences is that it provides
a language, a conceptual framework for describing relationships that would
be difficult to discuss in any other language. Some scientific principles
give information relating that values of variables at a given instant,
for instance Ohm's Law E=IR, or the Boyle-Charles Law for ideal gasses,
pV=kT. Calculus is not relevant for these rules. But many of the most
important principles in science are rules for the way variables change.
As shown above, physics tells you how velocity will change in various
situations -- i.e. it tells you about acceleration. This is why it's important
to have a mathematical way of talking about change. That's why you see
the concept of the derivative used throughout science -- in physics, chemistry,
biology, economics, even psychology.
Some basic examples are given here...
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